Use SimpleNamespace:
>>> from types import SimpleNamespace >>> d = dict(x=[1, 2], y=['a', 'b'])>>> ns = SimpleNamespace(**d)>>> ns.x[1, 2]>>> nsnamespace(x=[1, 2], y=['a', 'b'])↧
Answer by Dmitry Zotikov for How to use a dot "." to access members of dictionary?
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